Index Of Fun

Today's Puzzles

1. 1.    Sudoku

2. 2.    Wonder Word

3. 3.    Daily Crazy Quiz

4. 4.    Brain Teaser Contest

5. 5.    Themed Crossword

6. 6.    Word Jumble

7. 7.    Cryptogram

8. 8.    Kakuro

9. 9.    Word Search

10. 10.  Word Crunch

11. 11.  Word Square Puzzle

12. 12.  JigSaw

13. 13.  Anything Puzzles

14. 14.  All Our Daily Puzzles

Puzzle Zone Navagation

What's New?
Topic Of The Day
Interactive Puzzles
IQ Tests and Quizzes
Daily Videos
Jigsaw Puzzles
Word Puzzles
Sudoku Zone
Maze Zone
Mahjong Zone
"GRY" Puzzle
Trivia Zone
Daily Education
Ultimate IQ Test
Brain Bashers

    Our Fun Sites

A Fun Zone
A Puzzle Zone
A Game Zone
Top 100 Game Sites
Puzzle Store
Brain Teaser Archives
Fun Game Sites
A Free Zone

Daily Brain Teaser / Puzzle
December 12, 2006
Previous Days Teaser -- Want More? -- Next

Mr Smith, a commuter, is picked up each day at the train station at exactly 5 o'clock. One day he arrived unannounced on the 4 o'clock train and began to walk home. Eventually he met the chauffeur driving to the station to get him. The chauffeur drove him the rest of the way home, getting him there 20 minutes earlier than usual.
On another day, Mr Smith arrived unexpectedly on the 4.30 train, and again began walking home. Again he met the chauffeur and rode the rest of the way with him. How much ahead of usual were they this time?

VIEW SOLUTION BELOW

If you see this, you may need to update your browser.

THE SOLUTION

On the first day, the chauffeur was spared a 20-minute drive. Thus Mr Smith must have been picked up at a point which is a 10-minute drive, one way from the station. Had the chauffeur proceeded as usual, he would have arrived at the station at exactly 5 oclock. The 10-minute saving means that he must have picked up Smith at 4.50. Thus Smith took 50 minutes to walk what the chauffeur would take 10 minutes to drive. From this we see that the chauffeur goes five times as quickly as Smith. Now, on the second day, suppose that Smith walks for 5t minutes. The distance he covers, then, would take the chauffeur only t minutes to drive. Accordingly, Smith was picked up this time at t minutes before 5 oclock, that is, at 60 - t minutes after 4 oclock. However, starting at 4.30 and walking for 5t minutes, Smith must have been picked up at 30 + 5t minutes after 4 oclock. Hence 30 + 5t equals 60 - t, and t equals 5. Therefore the chauffeur was spared a 5-minute drive, each way, providing a saving of 10 minutes this time.